מתמטיקה תיכונית/אלגברה תיכונית/משוואות/משוואות פשוטות בנעלם אחד/תרגילים/רמה א: הבדלים בין גרסאות בדף

תוכן שנמחק תוכן שנוסף
דרורק (שיחה | תרומות)
אין תקציר עריכה
 
דרורק (שיחה | תרומות)
אין תקציר עריכה
שורה 2:
פתרו את המשוואות הבאות (מצאו את <math>\;x</math>)
#<math>
{-\frac{21}{32}}{-4\frac{1}{2}} = x
{-\frac{1}{34}}{-\frac{1}{4}} x
=
{\frac{1}{2}}{-1} x
+
{\frac{9}{2}}
{1} x
{-\frac{20}{3}}
</math>
#<math>
{\frac{1}{3}} x
+
{2}{-\frac{1}{3}} x
=
{-\frac{23}{34}} + x
{-2} x
{\frac{8}{3}}
{-\frac{39}{2}}
</math>
#<math>
{23}{-\frac{13}{2-4}{-4} =
{-43} x
{-1} x
+
{23}
{\frac{1}{2}}
</math>
#<math>
{-41}{-\frac{1}{4}} x
+
{\frac{1}{4}}{\frac{1}{4}}{-\frac{3}{2}}{-\frac{3}{2}} = x
{-\frac{1}{3}-1} x=
{-\frac{3517}{124}}
</math>
#<math>
{\frac{4-2}{3}-2} x
{-\frac{2}{3}}{-\frac{4}{3}} x
+
{12}{2} x
{-1}{-1} =
=
{-\frac{1}{32}}{-\frac{1}{2}}
</math>
#<math>
{1}{1}{-\frac{3}{2}}{-\frac{3}{2}} +
{-1} +
{\frac{1}{3}}{\frac{1}{3}} x
{3} x
{-\frac{4}{3}} x
=
{-13} x+
{-\frac{193}{32}}
</math>
#<math>
{-\frac{12}{-2}} x+
{1} x
+
{\frac{1}{2}}{-1} x=
{-2\frac{1}{4}} =+
{-\frac{313}{24}}
</math>
#<math>
{-1}{-1} +
{\frac{12}{3}}{-\frac{12}{23}} x
+
{\frac{3}{4}} x
=
{\frac{3}{4}} +
{-1} x
{-\frac{491}{124}}
</math>
#<math>
{3-\frac{1}{2}}{-\frac{41}{32}} = x
{-1}{-1}{-\frac{4}{3}}{-\frac{14}{3}} +=
{-\frac{1}{3}}{-3}
{6}
</math>
#<math>
{34}{4} + x
{-\frac{4}{3}}{-\frac{4}{3}} = x
{\frac{3}{2}} x
=
{-\frac{1}{2}}{-\frac{95}{6}}
{-4} x
+
{2} +
{\frac{21}{2}}
</math>
#<math>
{-\frac{34}{4}} x
+
{1}{1} x+
{\frac{1}{3}}{\frac{1}{3}} =
=
{\frac{1}{4}} + x
{\frac{109}{12}}
{-1} x
{-\frac{1}{4}}
</math>
#<math>
{-2}{2}{-1\frac{3}{4}}{-\frac{3}{4}} x
+
{\frac{2}{3}}{\frac{2}{3}} x=
{-\frac{3}{4}} +
=
{\frac{15}{2}}{-\frac{11}{612}}
</math>
#<math>
{-1}{-1}{-\frac{3}{2}}{-\frac{3}{2}} x
{3} x
{-1}{-1} +
+
{24}{-14} x
+
{\frac{2}{3}} x
=
{-12}
{\frac{38}{3}}
</math>
#<math>
{-1}{-1} x
{-\frac{1}{2}}{-\frac{1}{2}} x
{-1} =
{-\frac{1}{2}}{-4\frac{1}{2}} x
+=
{\frac{3}{2}}{-\frac{27}{2}}
{16}
</math>
#<math>
{\frac{4}{3}}{\frac{4}{3}} x
{4} x
{-1}{-1}{-2}{-2} =
+
{1}{-\frac{28}{3}}
{1} x
+
{3} =
{\frac{2}{3}} x
+
{\frac{22}{3}}
</math>
#<math>
{3-2}{-2} x
{-3}{-3}{-1}{-1} x
+
{\frac{1}{4}} x
{-3} x
=
{1\frac{2}{3}} x
{-25}
+
{\frac{3}{2}}
</math>
#<math>
{-\frac{13}{42}}{-\frac{3}{2}}{-1}{-1} + x
{-1}{-31} +=
{\frac{1}{3}} x
{-\frac{1}{2}}
=
{-\frac{41}{2}}
</math>
#<math>
{-\frac{41}{3}-1} x+
{\frac{3}{2}}{\frac{3}{2}} x
+
{\frac{2}{3}} +
{\frac{1}{2}} +
{3} x
=
{\frac{17}{6}}
</math>
#<math>
{-3} x
+
{1}{1} =
{2} x
+
{21} =
{\frac{1}{2}} x
{-7}
</math>
#<math>
{-1}{-1} x+
{\frac{1}{2}}{\frac{1}{2}}{-\frac{2}{3}}{-\frac{2}{3}} x
+
{1} x
+
{\frac{4}{3}} x
=
{1}{-\frac{11}{2}}
{2} x
+
{\frac{8}{3}}
</math>
#<math>
{-\frac{31}{2}-1}{-\frac{2}{3}}{-\frac{1}{2}} x
{-1}{-1} =
=
{\frac{34}{23}} x
{-\frac{56}{3}}
</math>
#<math>
{\frac{4}{3}}{\frac{4}{3}} +
{4}{4} =
{3} x
+
{3}{-\frac{2320}{63}}
</math>
#<math>
{\frac{1}{2}}{\frac{1}{2}}{-\frac{1}{2}}{-\frac{1}{2}}{-\frac{4}{3}}{-\frac{4}{3}} =
{-2} +
{1}{-\frac{1}{2}} x
{-\frac{40}{3}}
=
{\frac{1}{4}} +
{\frac{5}{4}}
</math>
#<math>
{-\frac{3}{2}}{-\frac{3}{2}}{-1}{-1} +
{\frac{14}{23}}{\frac{4}{3}} =+
{1}{1} =
{-\frac{3}{4}}{-\frac{4}{3}} +
{-\frac{491}{126}}
</math>
#<math>
{-\frac{1}{2}}{\frac{1}{2}} + x
{-\frac{1}{3}}{-\frac{1}{3}}{-\frac{3}{2}}{-\frac{3}{2}} = x
{2}{-\frac{5}{6}}
+
{\frac{1}{4}} =
{\frac{1}{4}} +
{7}
</math>
#<math>
{-21}{-1} + x
{\frac{-1}{3-1}} + x
{\frac{4}{3}} x
+
{\frac{1}{2}}{\frac{1}{2}} x
{1} =
{-\frac{1}{4}}{-\frac{1}{4}} x
{-2}
=
{-\frac{21}{4}}
</math>
#<math>
{2-\frac{1}{4}}{-\frac{41}{34}} = x
{\frac{-1}{4}-1} x
{-3} +
{\frac{294}{123}}{\frac{4}{3}} x
=
{-1} x
+
{\frac{13}{12}}
</math>
#<math>
{\frac{1}{2}}{\frac{1}{2}} +
{1} x
+
{\frac{1}{2}}{\frac{1}{2}} +
{2} x
{-1}{1} = x
{3}
=
{2} x
 
</math>
#<math>
{-\frac{1}{3}}{\frac{1}{3}}{-\frac{2}{3}}{-\frac{2}{3}} + x
+
{\frac{1}{4}} x
{1}{1} =
{-\frac{31}{2}}{-2} x
+
{\frac{7}{6}}
</math>
#<math>
{-\frac{1}{2}}{-\frac{1}{2}}{-\frac{1}{4}}{-\frac{1}{4}} x
=
{\frac{1}{2}} x
+
{\frac{41}{3}}{-\frac{7}{3}} +
{\frac{1}{3}} x
=
{\frac{65}{4}}
</math>
#<math>
{2-1}{-1} x
+
{\frac{1}{2}}{\frac{1}{2}} x
+
{\frac{3}{4}}{\frac{3}{4}} =
{2} x
{-\frac{37}{4}}
=
{\frac{3}{2}} x
{-\frac{3}{2}}
</math>
 
 
 
 
 
 
==תשובות סופיות==
#<math>
{34}
 
</math>
#<math>
{5-6}
 
</math>
#<math>
{-56}
 
</math>
#<math>
{-32}
 
</math>
#<math>
{16}
 
</math>
#<math>
{-23}
 
</math>
#<math>
{04}
 
</math>
#<math>
{-3}
 
</math>
#<math>
{-62}
 
</math>
#<math>
{2-6}
 
</math>
#<math>
{-12}
 
</math>
#<math>
{-24}
 
</math>
#<math>
{-4}
 
</math>
#<math>
{36}
 
</math>
#<math>
{1-4}
 
</math>
#<math>
{-26}
 
</math>
#<math>
{-63}
 
</math>
#<math>
{1-2}
 
</math>
שורה 320 ⟵ 294:
</math>
#<math>
{-45}
 
</math>
#<math>
{-3}
 
</math>
#<math>
{-56}
 
</math>
#<math>
{-42}
 
</math>
#<math>
{56}
 
</math>
#<math>
{-13}
 
</math>
#<math>
{51}
 
</math>
#<math>
{01}
 
</math>
#<math>
{0-4}
 
</math>
#<math>
{-42}
 
</math>
#<math>
{-54}
 
</math>