64 2 x − 1 = ( 1 8 ) x − 1 {\displaystyle 64^{2x-1}=({\frac {1}{8}})^{x-1}}
64 2 x − 1 = ( 1 8 ) x − 1 2 6 ( 2 x − 1 ) = 2 − 3 ( x − 1 ) 12 x − 6 = − 3 x + 3 15 x = 9 x = 9 15 = 3 5 {\displaystyle {\begin{aligned}64^{2x-1}=({\frac {1}{8}})^{x-1}\\2^{6(2x-1)}=2^{-3(x-1)}\\12x-6=-3x+3\\15x=9\\x={\frac {9}{15}}={\frac {3}{5}}\\\end{aligned}}}
